PLEASE I NEED HELP ASAP!!!!


Use Vertex form to write the equation of the parabola.

A. y = 3 (x+2)^2 + 2

B. y = 3 (x-2)^2 - 2

C. y = (x+2)^2+ 2

D. y = 3 (x-2)^2 + 2

PLEASE I NEED HELP ASAPUse Vertex form to write the equation of the parabolaA y 3 x22 2B y 3 x22 2C y x22 2D y 3 x22 2 class=

Respuesta :

The vertex form is
[tex]y = a {(x - h)}^{2} + k[/tex]
where a is the coefficient, and (h,k) is the vertex. Looking at the graph, we see that the vertex is (-2,2), so h is -2 and k is 2. We see that the parabola opens upwards, so A is positive, and is stretched by a factor of 3. (We can find this by looking where the (1,1) should be. We go over 1 from the parabola, and see where the y coordinate is. This is at (-1,5), or 1 unit right and 3 units up.) Therefore, our a is 3. Plugging this into the vertex form:
[tex]y = 3 {(x + 2)}^{2} + 2[/tex]
Which is answer A
filling this spot in and agree that the answer is A.