Respuesta :
Answer:- Oxidation half reaction is [tex]KNO_3 \rightarrow O_2[/tex]
and the reduction half reaction is [tex]KNO_3 \rightarrow KNO_2[/tex]
Explanations:- Oxidation number of nitrogen in nitrate(reactant side) is +5 and in nitrite(product side) it is +3. Here the oxidation number of nitrogen is decreasing from 5 to 3 which is reduction.
As per rules, oxidation number of oxygen in it's compounds is -2 and in elemental form it is 0. So, for the given reaction the oxidation number of oxygen is increasing from -2 to 0 which is oxidation.
The balanced chemical equation is, [tex]2KNO_3 \rightarrow 2KNO_2 + O_2[/tex]