x^2 + 8x +15 is the area
x+5 is the length
x+3 is the width
(x+5)(x+3)=
x^2 + 3x +5x +15
x^2 +8x + 15
Hope this helped!!!!
So since the area of a rectangle is A=bh, we just need to form our equation off of that. Our equation will look like this: [tex] l*2x(x-5)=6x^3-30x^2 [/tex]
Firstly, divide both sides by 2x(x-5): [tex] l=\frac{6x^3-30x^2}{2x(x-5)} [/tex]
Next, factor 6x^3-30x^2: [tex] l=\frac{6x^2(x-5)}{2x(x-5)} [/tex]
Next, cancel out (x-5): [tex] l=\frac{6x^2}{2x} [/tex]
Next, expand 6x^2: [tex] l=\frac{3*2*x^2}{2x} [/tex]
Next, divide and your answer will be: [tex] l=3x [/tex]
