Respuesta :

I think this is a bit of a trick question. One thing you cannot do is assume that p>q. The question gives you no indication that is true. If you assume that q>p then you do get an answer.


Givens

1<=q - p <=3

-11 <= q - p <= 29 Add

-10 <= 2q <= 32 Divide by 2

- 5 <= q <= 16


Now we need to change this so there are no equal signs.

-6 < q < 17 which is C. I'll post this and ask someone I know whom I think is around.

Ok, I'll try to explain my solution as best as I could.

If clarifications are needed, please do not hesitate.


We are given that both p and q are integers (i.e. positive, negative whole numbers or zero).


We will assume, without loss of generality, that

******* p >= q ********* .....................(1)


and in return, we have to make sure the inequalities have to be satisfied for BOTH p and q, because we don't know if q is actually greater than p.


Question says the positive difference between p and q is no more than 3. Expressed in an inequality,

p-q ≤ 3 ............................................(2)


Also, the sum of p and q must be between -12 and 30.

So

p+q ≥ -12 .......................................(3)


and

p+q <= 30 ..........................................(4)


Rewrite (2) as p ≤ q+3…………..(2a)

and substitute (2a) in (4)

q+q+3 ≤ 30 => 2q ≤ 30-3 => 2q ≤ 27 => q ≤ 13.5 =>

q ≤ 13 ………………………(5) because q is an integer.


Put (5) in (2a)

p ≤ 13+3 = 16

So the upper limit of p or q is 16.


Similarly,

Rewrite (2) as q ≥ p-3…………..(2b)

And substitute in (3),

p+(p-3) ≥ -12 => p+p ≥ -12+3 => 2p ≥ -9 => p ≥ -4.5 =>

p ≥ -4 ……………………(6) because p is an integer, and -4 >-4.5


Put (6) back in (2b)

q ≥ (-4) -3, or q ≥ -7


So the combined lower limit of p and q is -7


If we set Q = either (our) p or q, then

-7 ≤ Q ≤ 16


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