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A sample of water with a mass of 587.00 kg is heated with 87 kJ of energy to a temperature of 518.4 K. The specific heat of water is 1 J-1 kg K-1. What is the initial temperature of the water?

Respuesta :

Chlidonias

Heat, mass, specific heat and temperature difference are related by the equation:

[tex] q = mC [/tex]ΔT

[tex] 87 kJ * \frac{1000 J}{1 kJ} = 587.00 kg * (1\frac{J}{kg.K} ) * (518.4 K - T_{initial})\\
(518.4 K - T_{initial}) = 148.2 K\\
T_{initial} = 370.2 K [/tex]

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