We can use the Ideal Gas Law for this question:
[tex] PV=nRT [/tex]
So we need to solve the equation for n, the number of moles:
[tex] \frac{PV}{RT}=n [/tex]
Now we can plug in the values that we are given to solve for the number of moles:
[tex] \frac{(8.57atm)(7.68L)}{(\frac{0.0821 L *atm}{mol* K} )(355K)}=n [/tex]
[tex] \frac{65.8176}{29.1455} =n=2.26 [/tex]
So now we know that there are 2.26 moles of oxygen in the container.
Explanation:
It is given that volume is 7.68 L, temperature is 355 k and pressure is 8.57 atm. So, according to ideal gas equation PV = nRT.
Also, it is known that number of moles equal mass divided by molar mass.
Therefore, putting the given values into the ideal gas equation as follows.
PV = nRT
[tex]8.57 atm \times 7.68 L[/tex] = [tex]n \times 0.082 atm L/mol K \times 355 K[/tex]
n = 2.26 mol
Thus, we can conclude that the number of moles present in given oxygen is 2.26 mol.
