contestada

One long wire carries a current of 30 a along the entire x axis. a second long wire carries a current of 40 a perpendicular to the xy plane and passes through the point (0, 4, 0) m. what is the magnitude of the resulting magnetic field at the point y = 2.0 m on the y axis?

Respuesta :

magnetic field due to long wire is given by

[tex]B = \frac{\mu_o i}{2\pi r}[/tex]

Magnetic field due to long wire along x axis

[tex]B_1 = \frac{2*10^{-7} *30}{2}[/tex]

[tex]B_1 = 3 * 10^{-6} T[/tex]

Magnetic field due to long wire perpendicular to xy plane

[tex]B_2 = \frac{2*10^{-7} *40}{2}[/tex]

[tex]B_2 = 4 * 10^{-6} T[/tex]

Both magnetic fields are perpendicular to each other

Net magnetic field is given by

[tex]B_{net} = \sqrt{B_1^2 + B_2^2}[/tex]

[tex]B_{net} = 5 * 10^{-6} T[/tex]

Otras preguntas