Dorth1229 Dorth1229

23-07-2018
Mathematics

contestada

Given a mean of 61.2 and a standard deviation of 21.4, what is the z-score of the value 45 rounded to the nearest tenth?0.8−0.90.9−0.8

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belgrad belgrad

30-07-2018

Given: Mean μ = 61.2 and standard deviation σ =21.4

The Z score of the value x=45 is given by

Z = [tex] \frac{x - mean}{standard deviation} [/tex]

Z = [tex] \frac{45 - 61.2 }{21.4} [/tex]

Z = [tex] \frac{-16.2}{21.4} [/tex]

Z = -0.757

The z-score value for 45 rounded to nearest tenth is -0.8

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caboosebteam caboosebteam

08-12-2021

Answer: It is most likely -0.8

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