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Find the de broglie wavelength λ for an electron moving at a speed of 1.00×106m/s. (note that this speed is low enough that the classical momentum formula p=mv is still valid.) recall that the mass of an electron is me=9.11×10−31kg, and planck's constant is h=6.626×10−34j⋅s. g

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I18ntech

De-broglie wavelength for an electron is given by,

λ=h/mv

here, h= plank's constant= 6.626×10³⁴

m= mass of the electron= 9.11×10⁻³¹

v= velocity of the electron= 1.00×10⁶

Substituting the values,

λ=[tex] \frac{6.626*10^{-34}}{(9.11*10^{-31})(1.00*10^{6}} [/tex]

λ= 727.3 m

Hence, the de-broglie wavelength of the electron is 727.3 m.

poona2339

De Broglie's wavelength will be 0.727 nm

Wavelength Calculation Formula. Electromagnetic (EM) waves travel through the space (a vacuum and free space) at the speed of light of approx. 2.99792 x 10^8 m/s. The speed of light is often rounded up for ease of calculation to 3.00 x 10^8 m/s. The wavelength of the electromagnetic wave decreases with frequency. 100Hz has a wavelength of 3000km

We have given the speed of the electron [tex]v = 10^{6} m/sec[/tex]

Mass of the electron = [tex]9.11 * 10^{-31} kg[/tex]

Plank's constant [tex]= 6.624 * 10^{-34} js[/tex]

We have to find the De Broglie wavelength

De Broglie wavelength is given by  λ = [tex]\frac{h}{mv} = \frac{ 6.624 * 10^{-34}}{9.11*10^{-31} } * 10^{6} = 0.727 * 10^{-9}m[/tex]

So the wavelength will be 0.727 nm

How do you measure wavelength?

  • Use a photometer for measure the energy of a wave.
  • Convert the energy into joules (J).
  • Divide the energy by Planck’s constant, 6.626 x 10 -34, to get the frequency of the wave.
  • Divide the speed of light, ~300,000,000 m/s, by the frequency to get the wavelength.

Learn more about wavelength here https://brainly.com/question/4112024

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