The given equation representing the reaction of Aluminum with oxygen to form aluminum oxide is:
[tex] 4 Al(s) + 3 O_{2}(g) ---> 2 Al_{2}O_{3} (s) [/tex]
Δ[tex] S^{0}_{reaction} [/tex] = ΣnΔ[tex] S^{0}(products) -[/tex]Δ∑n[tex] S^{0}(reactants) [/tex]
= {2*51 J/(K.mol)} - {(4* 28 J/(mol.K)) + (3 * 205 J/(mol.K)}
= -625 J/(mol.K)
Therefore, the delta S for the reaction is -625 J/(mol.K)