They were 64th so 180-64 = 116 students were below them.
x = 116, y =1
(x + 0.5y / n) = 116 + 0.5*1 / 180 = 116.5 / 180 = 0.647 = 64.7%
Rounded to whole number = 65% = 65th percentile
Jesse's ranking is in the 65th percentile.
Since Jesse was ranked 64th in a class of 180, the number of people below him will be: = 180 - 64 = 116
Then, we'll use the formula (x + 0.5y/n) in solving the question. This will be:
= (x + 0.5y/n)
where,
x = 116
y = 1
n = 180
= [116 + 0.5×1)] / 180.
= 0.647
= 0.65
Therefore, he's in the 65th percentile.
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