Respuesta :

first off, let's put 8y - 5x = 11, in a slope-intercept form, so we can see what's its slope

[tex] \bf 8y-5x=11\implies 8y=5x+11\implies y=\cfrac{5x+11}{8}
\\\\\\
y=\stackrel{slope}{\cfrac{5}{8}}x+\cfrac{11}{8} [/tex]

so the slope of this line is 5/8, well then

[tex] \bf \stackrel{\textit{perpendicular lines have \underline{negative reciprocal} slopes}}
{\stackrel{slope}{\cfrac{5}{8}}\qquad \qquad \qquad \stackrel{reciprocal}{\cfrac{8}{5}}\qquad \stackrel{negative~reciprocal}{-\cfrac{8}{5}}} [/tex]

ashishdwivedilVT

The slope of a line that is perpendicular to the line whose equation is 8y-5x=11  is -8/5.

It is require to find the slope.

What is slope?

Numerical measure of a line's inclination relative to the horizontal. In analytic geometry, the slope of any line, ray, or line segment is the ratio of the vertical to the horizontal distance between any two points on it.

Given that:

The equation of a straight line in the form y = mx + b where m is the slope of the line and b is its y-intercept.

The given equation is

8y-5x=11

Take 5x to another side,

8y=5x+11

Divide both side by 8,

y=5/8x+11/8

On comparing with general form,

The slope of the line is

m=5/8

When two line are perpendicular one slope is negative reciprocal of another.

m1*m2=-1

Then the slope of perpendicular line on this line is  m=-8/5

Therefore, the slope of a line that is perpendicular to the line whose equation is 8y-5x=11  is -8/5.

Learn more about slope here:

https://brainly.com/question/10685148

#SPJ5

Otras preguntas