To the nearest square unit, what is the area of the regular heptagon shown below?

They did the hard part for us; usually we're given a radius and have to come up with the base and height of the isosceles triangles ourselves.
Here we have 7 triangles and we're given their base and height so,
[tex]A = 7(\frac 1 2) (27.6)(28.7) = 2772.42[/tex]
choice D
Area of the regular heptagon is 2772 square units.
A heptagon is a seven-sided polygon that has seven angles, seven vertices, and seven edges. They may have the same or different dimensions of length. It is a closed figure and a heptagon with all equal seven sides is called a regular heptagon.
Area of the regular heptagon = [tex]\frac{1}{2}[/tex] × n × s × r
Given
Side s = 27.6 units
Radius r = 28.7 units
Number of sides n =7
Area of the regular heptagon = [tex]\frac{1}{2}[/tex] × n × s × r
Area of the regular heptagon = [tex]\frac{1}{2}[/tex] × 7 × 27.6 × 28.7
= 2772.42 square unit.
Hence, area of the regular heptagon is 2772 square units.
Find out more information about hexagon here
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