Respuesta :
Since we already have the balanced equation, we know that the ratio between [tex] Na:Na_{2}O [/tex] is [tex] 4:2 [/tex] respectively.
So then we can set up a proportion to find the number of moles produced when 2.90 moles of Na react completely:
[tex] \frac{4mol_{Na}}{2mol_{Na_{2}O}} =\frac{2.90mol_{Na}}{xmol_{Na_{2}O}} [/tex]
Then we cross multiply and solve for x:
[tex] 4x=5.8 [/tex]
[tex] x=1.45 [/tex]
Therefore, we know that when 2.90 moles of Na react completely, there are 1.45 moles of [tex] Na_{2}O [/tex] that are produced.
2 moles of Na2O will be produced if 2.90 moles of Na react completely.
HOW TO CALCULATE NUMBER OF MOLES:
According to this question, sodium reacts with oxygen to sodium oxide (Na2O). The balanced equation is as follows:
4Na + O2 → 2Na2O
Based on the equation, 4 moles of Na produces 2 moles of Na2O.
Therefore, 2.90 moles of Na will produce 2.90 × 2/4 = 1.45 moles of Na2O.
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