For this case, what we must do is suppose that the object is a rectangular prism.
We have then that the surface area of the object is given by:
[tex] A = 2wl + 2wd + 2ld [/tex]
Where,
w: width of the rectangular prism
l: length of the rectangular prism
d: depth of the rectangular prism
Substituting values we have:
[tex] A = 2 (2.5) (2.0) +2 (2.5) (2.0) +2 (2.0) (2.0) [/tex]
[tex] A = 28cm ^ 2 [/tex]
Answer:
The object area is:
[tex] A = 28cm ^ 2 [/tex]
Note: for the problem to make physical sense, we assume that the length is 2 centimeters.
