We know the distance formula is
[tex] \sqrt{ (x_{2}-x_{1})^2+ (y_{2}-y_{1})^2 } [/tex]
9)
Here A( -4,2) and B(1,4)
So length of AB
= [tex] \sqrt{(1-(-4))^2+(4-2)^2} =\sqrt{5^2+2^2} =\sqrt{29} [/tex]
Also C(2,1)
Length of BC
= [tex] \sqrt{(2-1)^2+(-1-4)^2} =\sqrt{1^2+(-5)^2} =\sqrt{26} [/tex]
So we can see that length of AB is not equal to length of BC
11.
Now AB = [tex] \sqrt{29} [/tex]
Also C(2,-1) & D(4,4)
Length of CD
= [tex] \sqrt{(4-2)^2+(4-(-1)) ^2} =\sqrt{2^2+5^2} =\sqrt{29} [/tex]
Yes AB = CD
