Answer: Area of isosceles triangle would be 49.32 sq. ft.
Step-by-step explanation:
Since we have given that
Measure of vertex angle of an isosceles triangle = 26°
Length of each side of the triangle = 15 feet
So, Area of triangle would be
[tex]\dfrac{1}{2}\sin \theta\times a\times b\\\\=\dfrac{1}{2}\times \sin 26^\circ\times 15\times 15\\\\=49.32\ ft^2[/tex]
Hence, area of isosceles triangle would be 49.32 sq. ft.
