Answer : The molar ratio of C, N and O are 0.05 : 0.01 : 0.1 or 5 : 1 : 10
Explanation :
First we have to calculate the number of moles [tex]C,N\text{ and }O[/tex].
(1) 2.2 grams of [tex]CO_2[/tex]
First we have to calculate the moles of [tex]CO_2[/tex]
[tex]\text{Moles of }CO_2=\frac{\text{Mass of }CO_2}{\text{Molar mass of }CO_2}=\frac{2.2g}{44g/mole}=0.05moles[/tex]
Now we have to calculate the moles of carbon and oxygen.
As, 1 mole of [tex]CO_2[/tex] contains 1 mole of carbon
So, 0.05 mole of [tex]CO_2[/tex] contains 0.05 mole of carbon
The number of moles of carbon (C) = 0.05 mole
As, 1 mole of [tex]CO_2[/tex] contains 2 mole of oxygen
So, 0.05 mole of [tex]CO_2[/tex] contains [tex]2\times 0.05=0.1[/tex] mole of oxygen
The number of moles of oxygen (O) = 0.1 mole
(2) [tex]6.02\times 10^{21}[/tex] atoms of nitrogen.
As, [tex]6.02\times 10^{23}[/tex] atoms of nitrogen present in 1 mole of nitrogen
So, [tex]6.02\times 10^{21}[/tex] atoms of nitrogen present in [tex]\frac{6.02\times 10^{21}}{6.02\times 10^{23}}=0.01[/tex] mole of nitrogen
The number of moles of nitrogen (N) = 0.01 mole
From this we conclude that, the molar ratio of C, N and O are:
C : N : O = 0.05 : 0.01 : 0.1
or,
C : N : O = 5 : 1 : 10
Therefore, the molar ratio of C, N and O are 0.05 : 0.01 : 0.1 or 5 : 1 : 10
