Respuesta :
Answer: Molarity of a solution : 0.416 M
[tex]Molarity = \frac{(Moles of solute)}{(Volume of solution in L)}[/tex]
In our question LiI(Lithium Iodide) is solute and we need to find the moles of LiI.
Given grams of LiI = 27.8g , Volume of solution = 500 mL
[tex]Moles of LiI = \frac{Grams}{Molar mass}[/tex]
Molar mass of LiI = 133.85 g/mol
[tex]Moles of LiI = \frac{27.8g}{133.85\frac{g}{mol}}[/tex]
Moles of LiI = 0.208 mol
To find molarity we need volume of solution in 'L' , so we need to convert 500 mL to L.
1 L = 1000 mL
[tex](500 mL)\times \frac{(1L)}{(1000mL)}[/tex]
Volume = 0.5 L
[tex]Molarity = \frac{(Moles of solute)}{(Volume of solution in L)}[/tex]
[tex]Molarity = \frac{(0.208mol)}{(0.5 L)}[/tex]
Molarity = [tex]0.416\frac{mol}{L}[/tex] or 0.416 M
