Respuesta :

[tex] \bf \cfrac{1}{2}-3\left( \cfrac{1}{2}+1 \right)^2\implies \stackrel{\mathbb{PEMDAS}}{\cfrac{1}{2}-3\left( \cfrac{1+2}{2} \right)^2}\implies \cfrac{1}{2}-3\left( \cfrac{3}{2} \right)^2
\\\\\\
\cfrac{1}{2}-3\left( \cfrac{3^2}{2^2} \right)\implies \cfrac{1}{2}-3\cdot \cfrac{9}{4}\implies \cfrac{1}{2}-\cfrac{27}{4}\implies \stackrel{\textit{LCD of 4}}{\cfrac{2-27}{4}}
\\\\\\
-\cfrac{25}{4}\implies -6\frac{1}{4} [/tex]