We know that in two dimensional co-ordinate geometry, the distance,d, between any two points [tex] (x_1,y_1) [/tex] and [tex] (x_2,y_2) [/tex] is given by the formula:
[tex] d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]
We will use the above formula that Darko must have used to find the distance between the two points A(3,-4) and B(-1,3). In this case: [tex] (x_1,y_1)=(3,-4) [/tex] and [tex] (x_2,y_2)=(-1,3)[/tex].
Thus, the distance,[tex] d=\sqrt{(-1-3)^2+(3-(-4))^2}=\sqrt{(-4)^2+(7)^2}=\sqrt{16+49}=\sqrt{65}[/tex]
Therefore, the distance between the given points A(3,-4) and B(-1,3) is: [tex] \sqrt{65}[/tex] or 8.06 (approx).
