Respuesta :

tramserran

To find the inverse, swap the x's and y's and solve for y. Remember that a(x) represents y

y = [tex] \frac{1}{x} [/tex] - 2 given

x = [tex] \frac{1}{y} [/tex] - 2 x's and y's swapped

x + 2 = [tex] \frac{1}{y} [/tex] added 2 to both sides

y(x + 2) = 1 multiplied y on both sides

y = [tex] \frac{1}{x + 2} [/tex] divided (x + 2) on both sides

Answer: [tex] a^{-1} (x) [/tex] = [tex] \frac{1}{x + 2} [/tex]

choixongdong

a(x) = 1/x - 2

or

y = 1/x - 2

Switch x and y to find the inverse function

x = 1/y - 2

1/y = x + 2

y = 1 / (x + 2)


Answer

a^-1(x) = 1 / (x + 2)

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