how do you solve this equation

Remember the order of operations: Parentheses, Exponents, Multiplication/Division, Addition/Subtraction
Solve the expressions in parentheses first.
There is an expression within parentheses that is also in an expression within brackets. Solve that expression first:
[tex] 6 - 10 = -4 [/tex]
The expression in brackets will now read:
[tex] [4 - 3(-4)] [/tex]
Multiply 3(-4):
[tex] 3 \cdot -4 = -12 [/tex]
[tex] [4 - (-12)] [/tex]
Solve the expression:
[tex] 4 - (-12) = 4 + 12 = 16 [/tex]
The problem should now look like this:
[tex] (8-2)^2 + \frac{1}{4}(16) [/tex]
Solve the expression in parentheses that has an exponent:
[tex] 8 - 2 = 6 [/tex]
[tex] (6)^2 = 6 \cdot 6 = 36 [/tex]
Solve the term with 1/4 as a coefficient:
[tex] \frac{1}{4}(16) = 4 [/tex]
The expression should now look like this:
[tex] 36 + 4 = \boxed{40} [/tex]
The answer is 40.
(8 - 2)² + 1/4[4 - 3(6 - 10)]
Solve this expression using PEMDAS. (M/D and A/S are not in order, they are solved from left to right)
According to PEMDAS, we are going to solve inside the parentheses (brackets) first.
Solve (6 - 10) inside the brackets first.
Solve the multiplication inside the brackets (-3 * -4).
Add 4 + 12 inside the brackets.
Now solve (8 - 2) to complete the P step in PEMDAS.
Next step in PEMDAS is E, exponents. Solve (6)².
Next step in PEMDAS is M, multiplication, so multiply 1/4(16).
The last step is to add 36 and 4 together.