Answer-
Solution-
Let's assume n is the normal vector for the horizontal plane < 0, 0, 1 > .
The co-ordinate of the point is (-4, 0, -3)
The general equation of a plane is -
[tex]n \cdot <x-x_{0},y-y_{0},z-z_{0}> = 0[/tex]
[tex]\Rightarrow <0, 0, 1>\cdot<x-(-3), y-(0), z-(-3)> \ = 0[/tex]
[tex]\Rightarrow 0(x+4)+0(y)+1(z+3)=0[/tex]
[tex]\Rightarrow z=-3[/tex]
∴ The equation for a horizontal plane through the point (−4,0,−3) is z= -3
