conservation of momentum ... that before = that after ... change zero
Answer:
The change in momentum of the system due to the collision is 0 kg-m/s.
Explanation:
It is given that,
Initial velocity of car 1, [tex]u_1=25j\ m/s[/tex] (north)
Initial velocity of car 2, [tex]u_2=-15j\ m/s[/tex] (south)
Mass of each cars, [tex]m_1=m_2=1100\ kg[/tex]
It may be the case of elastic collision, such that they will exchange their velocities. So, the final speed of both the cars will be :
Final velocity of car 1, [tex]v_1=-15j\ m/s[/tex] (south)
Final velocity of car 2, [tex]v_2=25j\ m/s[/tex] (north)
The change in momentum of the system due to the collision is equal to the final momentum minus initial momentum. So, it is equal to 0 kg-m/s. Hence, the correct option is (d) " 0 kg-m/s".
