Answer:
The correct answer is option C.
Explanation:
Work done is defined as product of force applied on an object to displace it from one from position to another.
[tex]W.D=Force\times displacement\times cos\theta [/tex]
[tex]\theta [/tex]= Angle between the force and displacement vectors.
Force applied in the box ,F= 20N
Displacement of the box = d = 40 m
Angle between the force and displacement = [tex]\theta =45^o[/tex]
[tex]W.D=F.d\times \cos \theta [/tex]
[tex]=20 N\times 40 m\times \cos (45^o)[/tex]
=[tex]20 N\times 40 m\times 0.7071 =565.685 J\approx 5.6\times 10^2 J[/tex]
The work done is [tex] 5.6\times 10^2 J[/tex].
