A homeowner uses a snowblower to clear his driveway. knowing that the snow is discharged at an average angle of 40° with the horizontal, determine the initial velocity v0 of the snow when the dimension a = 19 ft. (round the final answer to two decimal places.)

Respuesta :

given that snow is projected at an angle of 40 degree

It range is given as a = 19 ft

[tex]a = 19 * 0.3048 = 5.8 m[/tex]

now we can use the formula of horizontal range

[tex]R = \frac{v_o^2 sin2\theta}{g}[/tex]

[tex]5.8 =\frac{ v_o^2 sin(2*40)}{9.8}[/tex]

[tex]5.8 = \frac{v_o^2 * sin80}{9.8}[/tex]

[tex]v_o^2 = 57.7[/tex]

[tex]v_o = 7.6 m/s[/tex]

so its initial speed must be 7.6 m/s