Answer:
Velocity of the dog relative to the road = 26.04 m/s 3.15⁰ north of east.
Explanation:
Let the east point towards positive X-axis and north point towards positive Y-axis.
Speed of truck = 25 m/s north = 25 j m/s
Speed of dog = 1.75 m/s at an angle of 35.0° east of north = (1.75 cos 35 i + 1.75 sin 35 j)m/s
= (1.43 i + 1.00 j) m/s
Velocity of the dog relative to the road = 25 j + 1.43 i + 1.00 j = 1.43 i + 26.00 j
Magnitude of velocity = 26.04 m/s
Angle from positive horizontal axis = 86.85⁰
So Velocity of the dog relative to the road = 26.04 m/s 86.85⁰ east of north = 26.04 m/s 3.15⁰ north of east.
The velocity of the dog relative to the road is [tex]\rm \bold \texttt{{ 26.04 m/s \texttt3.15^\cdot}[/tex] north of east.
Speed of truck = 25 m/s north = 25 j m/s
Speed of dog = 1.75 m/s
At an angle of [tex]\rm 35. 0^\cdot[/tex] east of north
= (1.75 cos 35 i + 1.75 sin 35 j)m/s
= (1.43 i + 1.00 j) m/s
Velocity of the dog relative to the road,
= 25 j + 1.43 i + 1.00 j
= 1.43 i + 26.00 j
Magnitude of velocity = 26.04 m/s
Angle from positive horizontal axis = [tex]\bold{ 86.85^\cdot}[/tex]
Velocity of the dog relative to the road
= 26.04 m/s [tex]\bold{ 86.85^\cdot}[/tex] east of north
= 26.04 m/s [tex]\bold{ 3.15^\cdot}[/tex] north of east
Hence, we can conclude that the velocity of the dog relative to the road is [tex]\rm \bold \texttt{{ 26.04 m/s \texttt3.15^\cdot}[/tex] north of east.
To know more about relative velocity, refer to the link:
https://brainly.com/question/12846122?referrer=searchResults
