Find the area of the sector formed by the given central angle θ in a circle of radius r. (Round your answer to two decimal places.)
θ = 15°, r = 7 m

Respuesta :

6.41 m² ( 2 dec. places)

area of sector(A) = area of circle × fraction of circle

A = πr² × [tex]\frac{15}{360}[/tex]

  = π × 7² × [tex]\frac{15}{360}[/tex]

= (49π × 15)/360 = 6.41



The area of the sector to two decimal places is 6.41m

The formula for calculating the area of a sector is expressed as:

[tex]A_s=\frac{\theta}{360} \times \pi r^2\\[/tex] where:

r is the radius of the sector

[tex]\theta[/tex] is the angle subtended by the sector

Given the following:

θ = 15°

r = 7 m

Substitute the given parameters into the formula

[tex]A_s=\frac{15}{360} \times \pi (7)^2\\A_s=\frac{15}{360} \times 49\pi \\A_s = \frac{15}{360} \times 153.86\\A_s=\frac{2307.9}{360}\\A_s=6.41m[/tex]

Hence the area of the sector to two decimal places is 6.41m.

Learn more here: https://brainly.com/question/16802755