Respuesta :
Answer : The weight of compound y would be removed is 3.6363 g.
Solution : Given,
Distribution coefficient, K = 10
Volume of ether (organic layer) = 100 ml
Volume of water (aqueous layer) = 100 ml
Total Weight of material dissolved = 4 g
Formula used :
[tex]K=\frac{[Solute]_{o} }{[Solute]_{aq}}=\frac{C_{o} }{C_{aq}}=\frac{W_{o}/V_{o} }{W_{aq}/V_{aq} }[/tex]
Where,
'O' repersent for organic layer and 'aq' repersent for aqueous layer.
[tex]C_{o}[/tex] and [tex]C_{aq}[/tex] are the concentration of organic solution and the concentration of aqueous solution respectively.
[tex]W_{o}[/tex] and [tex]W_{aq}[/tex] are the weight of material dissolved in each organic and aqueous layer respectively.
[tex]V_{o}[/tex] and [tex]V_{aq}[/tex] are the volume of organic and aqueous layer respectively.
Let, the weight of compound y removed '[tex]W_{o}[/tex]' is 'X' gram.
[tex]W_{o}[/tex] = X gram
[tex]W_{aq}[/tex] = Total weight of material - weight of compound y removed = 4 - X gram
Now put all the values in above formula,we get
[tex]K=\frac{W_{o}/V_{o}}{W_{aq}/V_{aq}}[/tex]
10= [tex]\frac{\frac{X(g)}{100(ml)} }{\frac{4-X(g)}{100(ml)} }[/tex]
Rearranging the terms, we get the value of X, as
X = 3.6363 g
