Respuesta :
Explanation:
(a) According to the given data, mass of the solution will be calculated as follows.
Mass of solution = Mass of KCl + Mass of water
= (40 + 225) g
= 265 g
Therefore, (m/m)% of KCl will be calculated as follows.
(m/m)% of KCl = [tex]\frac{\text{mass of KCl}}{\text{mass of solution}} \times 100[/tex]
= [tex]\frac{40}{265} \times 100[/tex]
= 15.09%
Hence, mass percent of KCl in the solution is 15.09%.
(b) Now, we will calculate the mole fraction of ionic species present in KCl in the solution are follows.
Molar mass of KCl is 74.55 g/mol.
Moles of KCl = [tex]\frac{mass}{\text{molar mass}}[/tex]
= [tex]\frac{40 g}{74.55 g/mol}[/tex]
= 0.536 mol
or, = 0.54 mol
As, molar mass of water is 18 g/mol. Hence, moles of water will be calculated as follows.
Moles of [tex]H_{2}O[/tex] = [tex]\frac{mass}{\text{molar mass}}[/tex]
= [tex]\frac{225 g}{18 g/mol}[/tex]
= 12.5 mol
So, total number of moles = moles of KCl + moles of [tex]H_{2}O[/tex]
= (0.54 + 12.5) mol
= 13.04 mol
Calculate the mole fraction of KCl in the solution as follows.
Mole fraction = [tex]\frac{\text{moles of KCl}}{\text{total moles}}[/tex]
= [tex]\frac{0.54 mol}{13.04 mol}[/tex]
= 0.041
Therefore, mole fraction of the ionic species KCl in the solution is 0.041.
A. The mass percent of KCl in the solution is 15.1%
B. The mole fraction of the ionic species KCl in the solution is 0.041
A. Determination of the mass percent of KCl in the solution.
Mass of KCl = 40 g
Mass of water = 225 g
Mass of solution = 40 + 225
Mass of solution = 265 g
Percentage of KCl =?
[tex]Percentage = \frac{mass of solute}{mass of solution} * 100\\\\= \frac{40}{265} * 100\\\\[/tex]
= 15.1%
Therefore, the mass percent of KCl in the solution is 15.1%
B. Determination of the mole fraction of the ionic species KCl in the solution
- We'll begin by calculating the number of mole in 40 g of KCl.
Mass of KCl = 40 g
Molar mass of KCl = 39 + 35.5 = 74.5 g/mol
Mole of KCl =?
Mole = mass / molar mass
Mole of KCl = 40 / 74.5
Mole of KCl = 0.537 mole
- Next, we shall determine the number of mole in 225 g of water, H₂O.
Mass of H₂O = 225 g
Molar mass of H₂O = (2×1) + 16 = 18 g/mol
Mole of H₂O =?
Mole = mass / molar mass
Mole of H₂O = 225 / 18
Mole of H₂O = 12.5 mole
- Finally, we shall determine the mole fraction of the ionic species KCl.
Mole of KCl = 0.537 mole
Mole of H₂O = 12.5 mole
Total mole = 0.537 + 12.5 = 13.037 mole
Mole fraction of KCl =?
Mole fraction = mole of element / total mole
Mole fraction of KCl = 0.537 / 13.037
Mole fraction of KCl = 0.041
Therefore, the mole fraction of the ionic species KCl is 0.041
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