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Quadrilateral JKLM has vertices J(8, 4), K(4, 10), L(12, 12), and M(14, 10). Match each quadrilateral, described by its vertices, to the sequence of transformations that will show it is congruent to quadrilateral JKLM.


O(10,1), P(6,7), Q(14,9), and R(16,7), S(4, 16), T(10, 20), U(12, 12), and V(10, 10)
,A (-8,-4), B (-4, -10), C (-12, -12),
and D (-14, -10),W (5,1), X (1,7), Y(9,9), and Z (11,7),


1. a sequence of reflections across the
x- and y-axes, in any order

2. a translation 3 units down and 3 units left

3. a translation 3 units left and 2 units up

4. a translation 2 units right and 3 units down

Respuesta :

JKLM → OPQR is (x + 2, y - 3)  ⇒2 right and 3 down    Answer: #4

JKLM → STUV has no relation

JKLM → ABCD is (-x, -y)  ⇒  reflection over both axes. Answer: #1

JKLM → WXYZ is (x - 3, y - 3)  ⇒ 3 left and 3 down. Answer: #2


Answer:

A (-8,-4), B (-4, -10), C (-12, -12),  and D (-14, -10) is Answer #1;

W (5,1), X (1,7), Y(9,9), and Z (11,7) is Answer #2;

O(10,1), P(6,7), Q(14,9), and R(16,7) is Answer #4.

Explanation:

A reflection across the x-axis will negate the y-coordinate, and a reflection across the y-axis will negate the x-coordinate.  We can see by comparing ABCD to the pre-image JKLM that the coordinates are negated; this means ABCD matches Answer #1.

A translation 3 units down will subtract 3 from the y-coordinate; a translation 3 units left will subtract 3 from the x-coordiante.  Comparing WXYZ to pre-image JKLM, we see that the x-coordinates are 3 smaller and the y-coordinates are 3 smaller.  This means that JKLM matches Answer #2.

Answer #3 has no match.

A translation 2 units right will add 2 to the x-coordinate; a translation 3 units down will subtract 3 from the y-coordinate.  Comparing OPQR to pre-image JKLM, we see that the x-coordinates are 2 larger and the y-coordinates are 3 smaller; this means that OPQR matches Answer #4.