The school play sold $550 in tickets one night. The number of $8 adult tickets was 10 less than twice the number of $5 child tickets. How many of each ticket were sold?

Respuesta :

8(2 x-10)+5x=550

16x-80+5x=550

21x=630

x=30

The number of tickets sold of child is 30, of adult is 50 and total 80.

What is an equation?

The definition of an equation in algebra is a mathematical statement that demonstrates the equality of two mathematical expressions. For instance, the equation 3x + 5 = 14 consists of the two expressions 3x + 5 and 14, which are separated by the 'equal' sign.

What equation will form for the given scenario and find the number of tickers sold.

Let x be the number of child ticket sold.

As the ticket of adult sold is 10 less than twice of child's ticket so the number of adults tickets sold is 2x-10.

The cost of a child ticket is $5. so, the revenue from the child's ticket is $5x.

The cost of a child adult is $8. so, the revenue from the child's ticket is $8(2x-10) or on simplifying it will be $(16x-80).

The total revenue is $550 so, the equation formed will be 5x+16x-80=550.

on solving the equation we will get x=30.

So, the number of tickets sold of child is 30.

The number of tickets sold of adult is 2*30-10=50.

The total number of tickets sold is 30+50=80.

Therefore, child-30, adult-50, total-80 tickets are sold.

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