Respuesta :
Fe+CuSO4⟶Cu+FeSO4
Given that
FeSO4 = 92.50 g
Number of moles = amount in g / molar mass
=92.50 g / 151.908 g/mol
=0.609 moles FeSO4
Now calculate the moles of CuSO4 as follows:
0.609 moles FeSO4 * 1 mole CuSO4 /1 mole FeSO4
= 0.609 moles CuSO4
Amount in g = number of moles * molar mass
= 0.609 moles CuSO4 * 159.609 g/mol
= 97.19 g CuSO4
Answer : The mass of [tex]CuSO_4[/tex] needed will be, 97.2 grams.
Explanation : Given,
Mass of [tex]FeSO_4[/tex] = 92.50 g
Molar mass of [tex]FeSO_4[/tex] = 151.908 g/mole
Molar mass of [tex]CuSO_4[/tex] = 159.609 g/mole
First we have to calculate the moles of [tex]FeSO_4[/tex].
[tex]\text{Moles of }FeSO_4=\frac{\text{Mass of }FeSO_4}{\text{Molar mass of }FeSO_4}=\frac{92.50g}{151.908g/mole}=0.609moles[/tex]
Now we have to calculate the moles of [tex]CuSO_4[/tex].
The balanced chemical reaction is,
[tex]Fe+CuSO_4\rightarrow Cu+FeSO_4[/tex]
From the balanced reaction we conclude that
As, 1 mole of [tex]FeSO_4[/tex] obtained from 1 mole of [tex]CuSO_4[/tex]
So, 0.609 moles of [tex]FeSO_4[/tex] obtained 0.609 moles of [tex]CuSO_4[/tex]
Now we have to calculate the mass of [tex]CuSO_4[/tex].
[tex]\text{Mass of }CuSO_4=\text{Moles of }CuSO_4\times \text{Molar mass of }CuSO_4[/tex]
[tex]\text{Mass of }CuSO_4=(0.609mole)\times (159.609g/mole)=97.2g[/tex]
Therefore, the mass of [tex]CuSO_4[/tex] needed will be, 97.2 grams.
