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If gas in a sealed container has a pressure of 50 kpa at 300 k, what will the pressure be if the temperature rises to 360 k? 161 kpa 16 kpa 60 kpa 41 kpa

Respuesta :

jacob193

[tex]60 \; \text{kPa}[/tex]

The pressure an ideal gas exerts on a sealed container of fixed volume is directly related to its temperature in degrees Kelvin. That is:

[tex]T_1 / T_2 = P_1 / P_2[/tex]

In this scenario:

  • [tex]T_1 = 300 \; \text{K}[/tex]
  • [tex]P_1 = 50 \; \text{kPa}[/tex]
  • [tex]T_2 = 360 \; \text{K}[/tex]

Rearranging gives

[tex]\begin{array}{lll}P_2 &=& P_1 \cdot T_2 / T_1 \\ &=& 50 \; \text{kPa} \times (360 \; \text{K})/ (300 \; \text{K})\\ &=& 60 \; \text{kPa}\end{array}[/tex]


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