Question 5:
a) Given: A parallelogram with base = 3.5 units and height = 2 units.
We have to determine the area of the parallelogram.
Area of parallelogram with base 'b' and height 'h' is given by the formula:
[tex]b \times h[/tex].
So, area of parallelogram = [tex]b \times h[/tex]
Area of parallelogram = [tex]3.5 units \times 2 units[/tex]
Area = 7 square units.
Therefore, the area of the parallelogram is 7 square units.
b) Given: A parallelogram with base = 3 units and area = 1.8 square units.
We have to determine the height of the parallelogram.
Since, area of parallelogram = [tex]b \times h[/tex]
1.8 square units = [tex]3 \times h[/tex]
h = [tex]\frac{1.8}{3}[/tex] units
h = 0.6 units
Therefore, the height of the parallelogram is 0.6 units.
c) Given a parallelogram with area = 20.4 square units and height = 4 units
We have to determine the base of the parallelogram.
Area of parallelogram = [tex]b \times h[/tex]
[tex]20.4 = b \times 4[/tex]
b = [tex]\frac{20.4}{4}[/tex]
b = 5.1 units
Therefore, the base of the parallelogram is 5.1 units.
a)
Area= 7 square units
b)
Height= 0.6 units
c)
Base= 5.1 units
We know that the area of a parallelogram with base b and height h is given by:
[tex]Area=b\times h[/tex]
a)
b=3.5 units
h=2 units
The area of parallelogram is:
[tex]Area=2\times 3.5\\\\Area=7\ \text{square units}[/tex]
b)
b=3 units
Area= 1.8 square units
Hence, we have:
[tex]1.8=3\times h\\\\h=\dfrac{1.8}{3}\\\\h=0.6\ \text{units}[/tex]
c)
Area= 20.4 square units
h=4 units
Hence,
[tex]20.4=4\times b\\\\b=\dfrac{20.4}{4}\\\\b=5.1\ \text{units}[/tex]
