Respuesta :
Solution-
We know that,
[tex]i=\frac{PRT}{100}[/tex]
Where,
i = interest generated,
P = principal = 1100,
R = rate of interest = 3.25%,
T = time period = 10 ( ∵ from January of 2003 to December of 2012 = 10 years),
Putting the values,
[tex]i = \frac{1100\times 3.25 \times 10}{100} = 357.5[/tex]
∴ Gerry's balance at the end of December of 2012 is (1100 + 357.5) = $1457.5
Answer:
$1,457.5
Step-by-step explanation:
Just did the lesson about simple interest.