A ball rolls down a hill, starting from rest. How long is it rolling if it accelerates at 3m/s2 and ends with a velocity of 35m/s?

Respuesta :

Answer

The answer to this question is [tex]11.67 s[/tex]

Explanation

As we know that accelartion is the rate of change of velocity. So, it can be write as

[tex]a = (V_f -V_i) /t[/tex]

where

[tex]V_f[/tex] is the final velocity

[tex]V_i[/tex] is the initial velocity

t is the time

a is the accelartion

as we konw

[tex]a = 3 ms^{-2}[/tex]

t = ?

From rest So,

[tex]V_i[/tex] = 0

[tex]V_f = 35 ms^{-1}[/tex]

Putting values

[tex]3 = (35 - 0)/t[/tex]

[tex]3 = 35/t[/tex]

[tex]t = 35/3[/tex]

[tex]t = 11.67 s[/tex]

So, the right answe is [tex]11.67 s[/tex]