A 100 cm3 block of lead weighs 11N is carefully submerged in water. One cm3 of water weighs 0.0098 N.
What volume of water does the lead displace?___
How much does that volume of water weigh?__
What is the buoyant force on the lead?___
Will the lead block sink or float in water?___

3. The same 100 cm3 block of lead is carefully submerged in a container of mercury. One cm3 of mercury weighs 0.13 N.
What volume of mercury is displaced?___
How much does that volume of mercury weigh?___
What is the buoyant force on the lead?___
d) Will the lead block sink or float in mercury?___

4. According to problems 2 and 3, does an object’s density have anything to do with whether or not it will float in a particular liquid? Justify your answer. ___

Respuesta :

#1

Volume of lead = 100 cm^3

density of lead = 11.34 g/cm^3

mass of the lead piece = density * volume

[tex]m = 100 * 11.34 = 1134 g[/tex]

[tex]m = 1.134 kg[/tex]

so its weight in air will be given as

[tex]W = mg = 1.134* 9.8 = 11.11 N[/tex]

now the buoyant force on the lead is given by

[tex]F_B = W - F_{net}[/tex]

[tex]F_B = 11.11 - 11 = 0.11 N[/tex]

now as we know that

[tex]F_B = \rho V g[/tex]

[tex]0.11 = 1000* V * 9.8[/tex]

so by solving it we got

V = 11.22 cm^3

(ii) this volume of water will weigh same as the buoyant force so it is 0.11 N

(iii) Buoyant force = 0.11 N

(iv)since the density of lead block is more than density of water so it will sink inside the water


#2

buoyant force on the lead block is balancing the weight of it

[tex]F_B = W[/tex]

[tex]\rho V g = W[/tex]

[tex]13* 10^3 * V * 9.8 = 11.11[/tex]

[tex]V = 87.2 cm^3[/tex]

(ii) So this volume of mercury will weigh same as buoyant force and since block is floating here inside mercury so it is same as its weight =  11.11 N

(iii) Buoyant force = 11.11 N

(iv) since the density of lead is less than the density of mercury so it will float inside mercury


#3

Yes, if object density is less than the density of liquid then it will float otherwise it will sink inside the liquid