Respuesta :
Slope-poitn form:
We need a point (x₀,y₀) and the slope (m).
y-y₀=m(x-x₀)
In this case:
(-9,-3)
m=-6
y+3=-6(x+9)
y+3=-6x-54
y=-6x-54-3
y=-6x-57
Answer: y=-6x-57
We need a point (x₀,y₀) and the slope (m).
y-y₀=m(x-x₀)
In this case:
(-9,-3)
m=-6
y+3=-6(x+9)
y+3=-6x-54
y=-6x-54-3
y=-6x-57
Answer: y=-6x-57
Answer: The required equation of the line is [tex]6x+y+57=0.[/tex]
Step-by-step explanation: We are given to find the equation that represents a line passing through the point (-9, -3) and has a slope of -3.
We know the following point-slope form :
Point-slope form : The equation of a line passing through the point (a, b) and having a slope of m is given by
[tex]y-b=m(x-a).[/tex]
For the given line, we have
(a, b) = (-9, -3) and m = -6.
Therefore, the equation of the line is
[tex]y-b=m(x-a)\\\\\Rightarrow y-(-3)=-6(x-(-9))\\\\\Rightarrow y+3=-6(x+9)\\\\\Rightarrow y+3=-6x-54\\\\\Rightarrow 6x+y+54+3=0\\\\\Rightarrow 6x+y+57=0.[/tex]
Thus, the required equation of the line is [tex]6x+y+57=0.[/tex]
