To do this, we need molar mass, as well as Avogadro's Number.
To start, 1.60 x 10-12 grams C10H16O. Molar mass = 152.23 g/mol
Divide 1.60 x 10-12 grams by 152.23 g/mol to get a number in moles.
You should get 1.05 x 10-14 moles
From here, we use Avogadro's Numner, 6.022 x 10^23 molecules/mole.
Multiply our moles, 1.05 x 10-14 by 6.022 x 10^23
Answer:
6.33 x 10^9 molecules.
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Answer : The number of molecules this quantity contains are [tex]6.32\times 10^{9}[/tex]
Explanation : Given,
Mass of [tex]C_{10}H_{16}O[/tex] = [tex]1.60\times 10^{-12}g[/tex]
Molar mass of [tex]C_{10}H_{16}O[/tex] = 152.23 g/mole
First we have to calculate the moles of [tex]C_{10}H_{16}O[/tex].
[tex]\text{ Moles of }C_{10}H_{16}O=\frac{\text{ Mass of }C_{10}H_{16}O}{\text{ Molar mass of }C_{10}H_{16}O}=\frac{1.60\times 10^{-12}g}{152.23g/mole}=1.05\times 10^{-14}moles[/tex]
Now we have to calculate the number of molecules of [tex]C_{10}H_{16}O[/tex].
As we know that, 1 mole of substance always contains [tex]6.022\times 10^{23}[/tex] number of atoms.
As, 1 mole of [tex]C_{10}H_{16}O[/tex] contains [tex]6.022\times 10^{23}[/tex] number of molecules.
So, [tex]1.05\times 10^{-14}moles[/tex] of [tex]C_{10}H_{16}O[/tex] contains [tex](6.022\times 10^{23})\times (1.05\times 10^{-14})=6.32\times 10^{9}[/tex] number of molecules.
Therefore, the number of molecules this quantity contains are [tex]6.32\times 10^{9}[/tex]
