ANSWER
Find out the how many pounds of nickel have to be used to create alloy that contains 4.9 lb of zinc.
To proof
As given
An alloy consists of nickel, zinc, and copper in the ratio 2:7:9.
the total part of the alloy are 18.
assuming one part be x.
thus
nickel part = 2x
zinc part = 7x
copper part = 9x
alloy that contains 4.9 lb of zinc.
than the equation becomes
7x = 4.9
[tex]x = \frac{4.9}{7}[/tex]
x = 0.7
Therefore
nickel part = 2x
= 2× 0.7
= 1.4 lb
1.4 lb of nickel have to be used to create alloy that contains 4.9 lb of zinc.
Hence proved
Answer:
1.08 lb
Step-by-step explanation:
let the quantity of nickel, zinc and copper in the alloy be 2x, 7x and 9x respectively.
as per the question, amount of zinc in the alloy is 4.9 lb
so, 9x = 4.9
x = 4.9 / 9
x = 0.54
so, quantity of nickel = 2x = 2 *.54 = 1.08
so, pounds of nickel required to create alloy = 1.08 lb
