asha141
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What is the solution to the inequality? -2/3(2x - 1/2) ≤ 1/5x - 1 Express your answer in interval notation.

This is my answer and work, is this right? And how would I put this in interval notation.
-2/3(2x - 1/2) ≤ 1/5x - 1
2x – 1/2 ≥ 1/5x +3/2
2x ≥ 1/5x + 2
9/5x ≥ 2
x ≥ 10/9

Respuesta :

ANSWER


[tex]-\frac{2}{3}(2x-\frac{1}{2})\le \frac{1}{5}x-1[/tex]


Multiply through by LCM of 15


[tex](15) \times -\frac{2}{3}(2x-\frac{1}{2})\le 15(\frac{1}{5}x-1)[/tex]





[tex] -10(2x-\frac{1}{2})\le 3x-15[/tex]



Expand brackets to obtain,



[tex] -20x+5\le 3x-15[/tex]



Group like terms



[tex] 15+5\le 20x+3x[/tex]




[tex] 20\le 23x[/tex]


[tex] \frac{20}{23}\le x[/tex]




[tex]x\ge \frac{20}{23}[/tex]


In interval form it is written as


[tex] [\frac{20}{23}, \infty)[/tex]