Initial velocity (Vi) = 25 m/s
acceleration (a) = [tex]-4 m/s^{2}[/tex]
time interval (t) = 5 sec
let us assume that final velocity after 5 sec be Vf
As acceleration is constant, we can apply the the equation of motion with constant acceleration i.e. [tex]V_{f} = V_{i} + at[/tex]
Hence, [tex]V_{f} = 25 +(-4)(5) = 25 -20 = 5 m/s[/tex]
so, the velocity of bicyclist will be 5 m/s after 5 sec
