Answer:
The voltage across resistor is [tex]E_{R}=96V[/tex]
Step-by-step explanation:
We are given with Voltage across terminals of a series RL circuit, [tex]E_{T}=120V[/tex]
And Resistance R=40Ω
And inductor reactance [tex]X_{L}=30[/tex]Ω
Since Resistor and inductor are in series, same current flows through both.
And that current, I = [tex]\frac{E_{T}} {Z}[/tex]
[tex]=\frac{120}{\sqrt{40^{2}+30^{2}}}= \frac{120}{\sqrt{2500}}[/tex]
= [tex]\frac{120}{50}=2.4A[/tex]
Therefore voltage across resistor, [tex]E_{R}=IR=2.4X40=96V[/tex]
