ANSWER
[tex]x=\frac{13}{62}[/tex]
and
[tex]y= \frac{-9}{62}[/tex]e have
EXPLANATION
[tex]17x-3y=4---(1)[/tex]
[tex]2x-4y=1[/tex]
Let us make y the subject and call it equation (2)
[tex]2x=1+4y[/tex]
[tex]x=\frac{1}{2}+2y--(2)[/tex]
We put equation (2) in to equation (1)
[tex]17(\frac{1}{2}+2y)-3y=4[/tex]
[tex]\frac{17}{2}+34y-3y=4[/tex]
[tex]34y-3y=4- \frac{17}{2} [/tex]
Simplify to get,
[tex]31y= \frac{8-17}{2} [/tex]
[tex]31y= \frac{-9}{2} [/tex]
Divide both sides by 31,
[tex]y= \frac{-9}{2} \div 31[/tex]
[tex]y= \frac{-9}{2} \times \frac{1}{31}[/tex]
[tex]y= \frac{-9}{62}[/tex]
We put this value in to equation (2) to get,
[tex]x=\frac{1}{2}+2\times -\frac{9}{62}[/tex]
[tex]x=\frac{1}{2} -\frac{18}{62}[/tex]
We collect LCM to obtain,
[tex]x=\frac{31-18}{62}[/tex]
[tex]x=\frac{13}{62}[/tex]
