If a bullet leaves the muzzle of a rifle at 600.0 m/s, and the barrel is 0.90 m long, what was the acceleration of the bullet while in the barrel?

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gefuerstenau gefuerstenau · Answer 1 · 2018-10-23T04:26:00+02:00

Use the kinematic vf^2 = vi^2 + 2a(x)

Using this, you get (600 m/s)^2 = (0m/s)^2 + 2a(.9m)

Solve for acceleration

a = 200,000 m/s^2

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ogorwyne ogorwyne · Answer 2 · 2021-09-09T14:57:40+02:00

The acceleration of the bullet while in the barrel = 200000m/s

To solve this problem we use this formula

v²-u² = 2as

This is the third equation used to find motion

Definition of parameters

Final speed = v = 600ms⁻¹

Distance covered = s = 0.9m

initial speed = u = 0

We are required to find the acceleration of the bullet

We put these values into the formula

600²-0² = 2*a*0.9

360000 = 1.8a

divide through by 1.8

[tex]a=\frac{360000}{1.8}[/tex]

a = 200000m/s

Therefore the acceleration is 200000 m/s

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