Respuesta :
Answer:
option 2=11/20 is the answer.
Step-by-step explanation:
given that there are 20 cards numbers 1,2... 20.
A card is randomly drawn.
We have to find the probability of drawing either 1 or even card.
P(drawing even card) = no of even cards/total cards = 10/20= 0.5
P(drawing one) = no of 1's/total cards = 1/20 = 0.05
P(drawing both one and even card) = 0 (since impossible)
Hence P(drawing even or one) =0.5+0.05-0
=0.55
= 11/20
Hence option 2 is the answer.
Answer : 11/20
There are 20 cards labeled from 1 to 20 in a bag. A card is randomly selected from the bag.
Total number of outcomes = 20
outcomes of an even number ={2,4,6,8,10,12,14,16,18,20}
So number of outcomes of even number = 10
outcomes of a 1 ={1}
So number of outcomes of a 1 = 1
Number of outcomes of even number and a 1 = 10+1 = 11
Probability ( any event) =number of favorable outcomes divide by total number of outcomes
Probability (getting an even number or a 1) = [tex]\frac{11}{20}[/tex]
