Consider two functions: g(x)=−x2−6x and the quadratic function f(x) shown in the table.

Which statements are true?

Select each correct answer.

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carlosego carlosego · Answer 1 · 2018-10-23T07:26:14+02:00

Answer:

1) The third option.

2) The last option.

Step-by-step explanation:

1) f(x) is greater on the interval (0,3), which is opened, because if you substitute [tex]x=2[/tex] you obtain the following result

[tex]f(2)=4\\g(2)=(2)^{2}-6(2)=-8[/tex]

3) If [tex]x=3[/tex], you obtain that:

[tex]g(3)=-9\\f(3)=9[/tex]

Therefore: [tex]f(3)>g(3)[/tex]

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lisboa lisboa · Answer 2 · 2018-10-23T07:31:23+02:00

Answer : a, c, d

[tex]g(x)= -x^2-6x[/tex]

x f(x) g(x)

-3 9 -27

-2 4 -16

-1 1 -7

0 0 0

-3 9 -27

-2 4 -16

-1 1 -7

(a) On the interval [0,3] f(x) is increasing and g(x) is decreasing. So rate of change of f(x) is greater than rage of change of g(x)

(b) f(x) and g(x) has same y intercept 0. so part b is not true

(c) f(x) is positive on the interval [0,3] . so f(x) is greater than g(x)

(d) g(3) = -27 and f(3) = 9. so g(3) is less than f(3)