when two vectors are inclined at some angle to each other then the magnitude of resultant of two vectors is given as
[tex]R = \sqrt{A^2 + B^2 + 2AB cos\theta}[/tex]
here A and B are the magnitude of two vectors and theta is the angle between them
now here we know that two vectors are of magnitude 0.25 m/s^2 each and they are inclined at angle of 45 degree
now we will plug in all data above
A = B = 0.25
[tex]\theta = 45[/tex]
[tex]a_{net} = \sqrt{0.25^2 + 0.25^2 + 2*(0.25)(0.25)cos45}[/tex]
[tex]a_{net} = 0.46 m/s^2[/tex]
So the magnitude of resultant acceleration will be 0.46 m/s^2
